We did indeed get the ten intervals we wanted. Now, let's try the other method and set the length of intervals instead of their number. We will use **the same commands** as in the previous example, but we will **change** the `breaks`

argument.

Instead, we will write:

split <- cut(vector, breaks = seq(start, end, by = length), include.lowest = TRUE )

This time, we will use a **vector** for the `breaks`

argument. When we use a vector, the `cut`

function will derive interval limits from the vector's values; it will then sort the dataset's values into these intervals. If we want to create a range of intervals with a **fixed length**, we need a **sequence of numbers**. We'll use the `seq`

function for this. We showed it above, but here it is again:

seq(start, end, by = length)

This function creates a **vector of numbers**, starting with the `start`

value, increasing the value of each number by the amount defined as the `length`

, and then stopping at or near the `end`

value. For example `seq(0,10, by=2)`

will create a vector with the numbers **0,2,4,6,8,10**. Giving this vector as the `breaks`

argument `cut`

function will create intervals like **[0,2], (2,4], (4,6], (6,8], (8,10]**.

To count the **frequencies of values** for each interval, we use the same code as before. First, we create a **data frame**:

split_df <- data.frame(interval=split)

Then we count interval frequencies:

count(split_df, interval)