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Nested CTEs


Alright, let's get started! We're going to tackle nested CTEs.

If you take a look into any database documentation, you will find out that you cannot put one CTE inside the parentheses of another CTE. Luckily, we can still use a simple technique to create nested CTEs. Take a look at the query:

WITH total_salesman AS (
  SELECT AS s_id, AS c_id,
    SUM(distance) AS sum_kilometers
  FROM salesman s 
  JOIN daily_sales ds 
  JOIN city c 

max_salesman AS (
    MAX(sum_kilometers) AS max_kilometers
  FROM total_salesman
  GROUP BY c_id

FROM max_salesman;

The trick is that the second query, max_salesman, uses the first CTE, total_salesman, in the FROM clause (FROM total_salesman). That means that once we define the first CTE, we can freely use it in subsequent CTEs.

Now, what does that query do? In the first CTE, we find the total number of kilometers driven in each city by each salesman (on all days). In the second CTE, we take these sums and choose the salesman with the maximal distance in each city. Finally, in the outer query, we find the average maximal distance across all cities.

As you know, it's impossible to use one aggregate function inside another. Nested CTEs are a simple way to get rid of that restriction.


Now it's your turn! In this part, we will clearly state each step you need to take so that you don't get confused.

First, find daily sums of amount_earned in each city. Then, find the average daily amount for all cities for all days. Finally, show the id and name of each city plus the number of daily sums that exceeded the average daily amount for each given city.

Stuck? Here's a hint!

SUM amounts earned in the first CTE, then find the average in the second CTE. In the outer query, use COUNT and make use of the results from both CTEs in the WHERE clause:

WHERE sum_amount > avg_amount